converting .bat file in .sh file

[shammi07]

Hi
I have to convert the following .bat file content in the .sh file

set "JAVA_OPTS=%JAVA_OPTS% -Djava.naming.factory.initial=org.jnp.interfaces.Na mingContextFactory"

set "JAVA_OPTS=%JAVA_OPTS% -Djava.naming.provider.url=jnp://localhost:1099"


set "SECURITY_OPTS= -Djava.security.auth.login.config=D:\jboss-5.0.0.CR2-jdk6\jboss-5.0.0.CR2\server\default\conf\jaas-standard.cfg"

set JAVA_OPTS= %JAVA_OPTS% %SECURITY_OPTS%

echo %JAVA_OPTS%


I converted in the following form

JAVA_OPTS="$JAVA_OPTS -Djava.naming.factory.initial=org.jnp.interfaces.Na mingContextFactory"

JAVA_OPTS="$JAVA_OPTS -Djava.naming.provider.url=jnp://localhost:1099"

SECURITY_OPTS="-Djava.security.auth.login.config=<jboss>/server/default/conf/jaas-standard.cfg"

export JAVA_OPTS= "$JAVA_OPTS $SECURITY_OPTS"


I am getting the error that
: command not found :
: command not found5 :


I am not getting what is wrong in the sh file.
Please help me resolve the problem.

Thanks

[Irithori]

Does the .sh file have windows style line feeds by any chance?
You can check by either cat -A <SH_FILE> or opening in vim and setting: set list or maybe your graphical editor tells you.

Either way, shell scripts need unix style line feeds.