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Hello everyone! I'm playing with an old VGA webcam and I'm not an expert with Linux. My question is: is there any way to get some information about what's happening ...
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  1. #1
    Just Joined!
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    Mar 2013
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    How to catch information from a device?


    Hello everyone!

    I'm playing with an old VGA webcam and I'm not an expert with Linux.
    My question is: is there any way to get some information about what's happening to the camera?
    I mean: on the top of my webcam there's a button but nothing happens if I try to push it whilst, say, `cheese` is opened, for instance.
    Moreover, if I launch from the shell dmesg that's the output -since the moment I plug the webcam-
    Code:
    $ dmesg
    (...)
    [ 4636.720294] usb 2-1.2: new full-speed USB device number 4 using ehci_hcd
    [ 4636.814502] usb 2-1.2: New USB device found, idVendor=093a, idProduct=2600
    [ 4636.814508] usb 2-1.2: New USB device strings: Mfr=1, Product=2, SerialNumber=0
    [ 4636.814511] usb 2-1.2: Product: VGA Single Chip
    [ 4636.814514] usb 2-1.2: Manufacturer: Pixart Imaging Inc. 
    [ 4636.814904] gspca_main: pac7311-2.14.0 probing 093a:2600
    [ 4636.817089] input: pac7311 as /devices/pci0000:00/0000:00:1d.0/usb2/2-1/2-1.2/input/input13
    but nothing more is printed out if then I push the button which is on the top of the webcam. Why? I mean, is dmesg the right tool to investigate this kind of information, or it's the webcam that does not react?

    Note: I'm using Ubuntu 12.10 (64 bit).

  2. #2
    Just Joined!
    Join Date
    Jun 2012
    Posts
    12
    What do you want to do? There are some technologies which abstract the webcam and allow you to access a kinda like framebuffer with some basic API. I think it resides in libv4l library. man is man's best friend when it comes to learning new libraries ;D

    And I think if you look through the dev folder, you should beable to get raw information out there...
    What I would do is try and find the specification for web cam's - how they send information, and research it. but I have too much time on my hands ;P

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