command that displays alphabet

[brucewayne3210]

This is rather foolish but kind of helpful. Does anyone know of command that will display A-Z out on separte lines, for instance the seq command works like this with numbers. seq 0 9 will display 0 thru 9 on seprate lines. Does anyone know how to do this using letters. Thanks

[myrdos]

I don't know if there's a way to do this in Linux already, but here's a simple program for you:

#include <iostream>

using namespace std;

int main(void)
{
for (char letter = 'A'; letter <= 'Z'; letter++)
cout << letter << endl;
}//main

1) Save it as az.cpp

2) g++ az.cpp -o az

2.5) If g++ command not found:
su -c 'apt-get update'
su -c 'apt-get install g++'

3) This produces the executable az. Run it with
./az

-Hope this helps,
Dave

[tpl]

welcome to the forum

you could use the shell, like this:

for i in A B C ... X Y Z
do
echo $i
done

[brucewayne3210]

yeah thanks guys i was just looking for a specific command. i will just write it out. I was writing a program that was going to do some character replacement. It would have been nice to just have a seq command for characters that would have been lovely versus typing out A B C D E F G and so on then lower case but oh well. I will get it done. thanks dudes.