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I installed 3pcs of 512M(DDR400) ram & 1pc of 256M(DDR333) ram into my machine.but just show 884M is it something wrong?
Code:
/proc# free -m
total used free shared buffers ...
- 09-01-2005 #1Just Joined!
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my ram = ?
I installed 3pcs of 512M(DDR400) ram & 1pc of 256M(DDR333) ram into my machine.but just show 884M is it something wrong?
Code:/proc# free -m total used free shared buffers cached Mem: 884 350 533 0 65 160 -/+ buffers/cache: 124 760 Swap: 2219 0 2219
- 09-01-2005 #2Linux Newbie
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how lucky can a guy get? put 512 in and get 884 out!
seriously I have no idea maybe one of the mem chips is more than you thought it was.
- 09-01-2005 #3forum.guy
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Check your motherboard manual to see if it will accept that combination of RAM, and in the order in which you installed them into the slots. Also make sure all the RAM you selected is compatible with your motherboard.
If you don't have the manual, it's probably available online.
- 09-01-2005 #4Linux Enthusiast
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3 x 512 + 256 >> 884
Originally Posted by robotics56a
that's the problem
threadstarter, i wish i could help you on this one
. try what the above poster said
- 09-01-2005 #5Linux Newbie
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my fail math thats... oh.
Originally Posted by josolanes
btw its > or >= not >>
ya try what he said. if you cards are void of labels you'll have to do the binary aproach (nearly all combinations) just see 1st if there are any 2 cards that work together and keep going
- 09-01-2005 #6Just Joined!
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I checked the manual, It is Intel D865GLC, it suports max to 4G of Ram, 333 and 400 of Ram are compatible.
Originally Posted by Ozar
http://www.intel.com/design/motherbd/lc/[/url]
o.k. I will go ahead for combination.


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