jaay

i'm supposed to code a linux shell script named fileinof which allows users to view info on files in a specified directory and the script will accept one optional parameter as a directory path.

here's what i got so far

$ cat fileinfo
#!/bin/s

if [ $# -ne 1 ]; then
echo 1>&2 Usage: fileinfo [directory path]
exit 127
fi


but at the command line when i enter $ ./fileinfo it says bash: $: command not found. WHY? am i missing something? i can't figure it out.

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vsemaska

Could be the 1st line:

#!/bin/s

Should be:

#!/bin/bash

jaay

I fixed that problem, but it still gives me the same error:

bash: $: command not found

likwid

You are typing $ then the command. You need not type the $.

vsemaska

How are you trying to run the script. It should be:

./fileinfo

Also you need quotes around the error message:

echo 1>&2 'Usage: fileinfo [directory path]'

Franklin52

Make the file executable with the chmod command.

Regards

jaay

thank you! i feel like such an idiot.

how would i process the files in the directory that was entered?

jaay

or i mean how would i check if that directory existed?

Franklin52

You can do that with the test command.
I highly recommend you to read something about shell scripting. Go here for the tutorials:

Linux Shell Scripting Tutorial - A Beginner's handbook
http://www.tldp.org/LDP/Bash-Beginne...tml/index.html
http://tldp.org/LDP/abs/html/


Regards