[inderPunj]

Hi All,

I want to create a script in which i want to fulfill three conditions with awk command.
I want to search from a sentence if there is sel at the end of string, then it append "_aa01", if it has del at end it will append "_bb01", if nothing between both conditions it will append "$DATE"

if i can satisfy these all three conditions without awk, please let me know with examples.

Please help.

Thanks,
Inder Punj

[radoulov]

Please post sample input and an example of the desired output.

[inderPunj]

The 3 comdition should be as follows :-
1. Let i have inder_eatapple_sel then it will append _aa01 at the end, LIKE - inder_eatapple_sel_aa01
2. If i have inder_eatapple_del then it will append _bb01 at the end LIKE - inder_eatapple_del_bb01
3. if it has not sel nor del at the end, then it append current date.

Please suggest, if want more clearification , please let me know.

Thanks,
Inder

[radoulov]

Yes,
as I said, post sample from the input and example (not description) of the desired output.

[scm]

Seems a pretty clear statement of the requirement to me.

awk '
/_sel$/  {print $0 "_aa01"; next}
/_del$/  {print $0 "_bb01"; next}
             {print $0 "_'$(date +%Y%m%d)'"}' inputfile

Adjust the date command to give the format you require (but avoid including slash characters (/)!).

[radoulov]

This should be sufficient:

awk '
$0=$0"_"(/[sd]el$/?(/_sel$/?"aa":"bb")"01":d)
' d="$(date +%F)" file

Avoid calling the external date command for every matching record ...

I prefer to have an example in/output though ...