[goude]

Hi everyone,

I am trying to write a small script that can output the RAM size.
I am doing this with the following command line:

system ("free -m | grep Mem");

The output I get is:
Mem: 999 916 83 0 106 265

Is there a way so that I can print out only the RAM size, which is the first number in the above row?

Thank you

[coopstah13]

cat /proc/meminfo | grep MemTotal

[bigtomrodney]

Try using awk

free -m |grep Mem |awk '{print $2}'

There are lots of ways to do this however. How about...

grep MemTotal /proc/meminfo

Though this again would require awk or similar to parse it.

EDIT :- Beat me to it Coopstah

[goude]

Thank you very much guys