wxjeacen

/*This program is to permute some letters of alphabet.
However i can not compile it .
There are always many errors.
your help will be appreciated deeply.
I am a new guy in Ubuntu .*/

#include<stdio.h>
#include<string.h>
int L;
void insort(int n,char *s,char c[]);


void insort(int n,char *s,char c[])
{
char *d;
char *str1,*str2;
int i;
if(n==0) *s=c[n];
for(i=n;i>=0;i--)
{ d=s;
memcpy(str1,d,i);
str2=d+i;
strcat(str1,c[n]);
strcat(str1,str2);
d=str1;
if (n==L)printf("%s\n",d);
}
if (n+1<=L)
insort(n+1,s,c);


}




int main()

{ char *str='\0';

char S[];
printf("The letters to permuted are:");
scanf("%s
",S);
L =strlen(S);

insort(0,str,S);

printf("\n");
return 0;

}

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wowbag1

Hi,
after giving a size to char S[] and scanf() put on one line.
Compiling it I found only one major error and that was

arg 2 of strcat is pointer from integer without a cast.

so check casting in C then it will not get seg fault - which I am assuming you are getting.

wxjeacen

/*I revised my programe ,corrected the error of the usage of "strcat".
still I can`t pass the compiling .
would someone post the code that can be compiled correctly .
your help will be well appreciated .
the code i given below */



#include<stdio.h>
#include<string.h>
int L;
void insort(int n,char s[],char c[]);


void insort(int n,char s[],char c[])
{
char d[50];
char str1[50],*str2;
int i;
if(n==0) s[n]=c[n];
else{ for(i=n;i>=0;i--)
{ memcpy(d,s,strlen(s));
d[strlen(s)]='\0';
memcpy(str1,d,i);
str1[i]='\0';
str2=d+i;
strcat(str1,c[n]);
strcat(str1,str2);
//d=str1;
memcpy(d,str1,strlen(str1));
d[strlen(str1)]='\0';
if (n==L)printf("%s\n",d);
}
}
if (n+1<=L)
insort(n+1,s,c);


}




int main()

{ char str[1000];
str[0]='\0';

char S[]="abcd";

L =strlen(S);

insort(0,str,S);

return 0;

}

gerard4143

could you post your makefile and the error(s)...Thanks