tanweeyang

Hi guys, i'm sure the question been asked before, but i'm a Linux script newbie, so i don't really know how to get things started. i have a task of reading in particular filename and finding out the particular extensions, so that i could do some processing on that file with that extension. like for a MyProgram.java file, i would open an new vi editor to allow edit, a MyWebPage.html, i would open an new browswer to view the page.

How do i check the file extensions ? I thought of several algorithms using the string expressions provided. Could anyone give any pointers ??

regards

kkubasik

That would requrire basicaly a massive parsing engin, the the specifics are elusive, and language specific, for example, the newer Java API's have some nice string tokenizers that make this process extrodinarly simple. But also, note that linux stores the information needed to open a file with the proper application in the file, not the extension, the extension is just a human readable component that windows decided to rely on, and became the windows standard, but if you ever write a script, you learn that the header is

#!/bin/bash

telling linux to open the program in /bin/bash.. to create a parsing engine to handle something of this magnetude is really a waste of time, but thats all it would be, something like perl (with its large library support) will make the mechanics of the task simpler, but in the end, its gonna be one massive *** switch/ifelse chain to get it done.

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tanweeyang

yeah how i wish i could have used java,but problem this is part of my assignment specifications and i got to adhere to the specs. I tried using string expression like $ expr index program.java .java" it returns the index of the dot and not whether its a java file extension.

It will be great if anyone out there could redirect me to any website or existing threads with similar questions ?

regards

IsaacKuo

Umm...what are your assignment specifications? You haven't said anything about what sort of tools you are allowed to use.

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tanweeyang

I been provided with several predefined java classes, and i am supposed to use this java programs to help me. The java programs provided each have a seperate, one being able to display the contents of a piped result into a list box, a dialog box that returns 1 or 0 to standard in and a simple JTextArea for simple editing.

I need to check the file extension, in order to prompt the apporiate action, like .java files to either compile or edit, class files to run etc..

I have to use the Bourn shell to write a script to do just that.

ninja972

I am not sure I understood you want but if you just need a shell script to get file extention:will output the the extention of the file.

asvija

I think you can use case st. of bash like this

#!/bin/bash

filenames=`ls`
for eachFile in $filenames
do
case $eachFile in
.c) echo $eachFile is a C file
;;
.java) echo $eachFile is a Java source.
;;
esac
done

asvija

Sorry, I missed out * in the cases. It should be like this

case $eachFile in

*.c) #some actions
;;
*.java) #some thing else
;;

esac