Command to Find and Replace the word

[DeeptiReddy]

Hi

I need to replace this word https://$test with $test.... I have tried this using the sed command like sed -i 's/https://$test/$test/g' test.php.. but I am not getting the desired output....
Please can anyone help me how to do this.... Thanks.

[Kieren]

You were almost there with your sed command but you need to escape your forward slashes in the http:// so that sed doesn't get confused by them. You simply do this by preceding each one with a backslash like this:

sed -i 's/https:\/\/$test/$test/g' test.php

[DeeptiReddy]

Thank you very much.. This command worked for me.. and I have one more question .. Can u pls say how to check the files list having this variable $test... I mean command to search the word in list of scripts.. I used find command find *.php -name $test but not working..... Thanks.

[Kieren]

Try using grep instead:

grep $test

[DeeptiReddy]

Sorry, Not able to find the result from the above ... getting the msg like "Usage: grep [option]..pattern [file]".. but in this directory I am having the scripts using the $test variable.

[Kieren]

Sorry, try:

grep $test *.php

[DeeptiReddy]

I have executed the above..But not getting any o/p.
..../TEST # grep $test *.php...

[Kieren]

You need to escape the $ symbol sorry. Also if you just want a list of filenames use the -l argument:

grep -l \$test *.php

[DeeptiReddy]

Thank You.

[tetsujin]

You were almost there with your sed command but you need to escape your forward slashes in the http:// so that sed doesn't get confused by them. You simply do this by preceding each one with a backslash like this:

sed -i 's/https:\/\/$test/$test/g' test.php

Or, somewhat easier - by replacing the slashes in the "search-and-replace" pattern with another character, you can use slashes inside the pattern without escaping them:

sed -i "s#https://$test#$test#g" test.php