Question concerning Grep

[mattseanbachman]

Hello All,


Glad they have a newbie forum, as I'm sure that this classifies as a newbie question. I'm working on a project that involves my using GNU grep, and I'm stuck on a step that is probably easier than I think.

Take this expression: grep -Pl "\xFF\xD8\xFF" ./*

This searches through files in current directory and outputs those that match having a file signature of FFD8FF, which are jpegs. What I'm trying to do is to do the same without the -P switch, but I'm woefully unskilled with non-Perl regex. I've tried the -al and -l switches to no avail.

Also, I have done my research into Google, to quell those who would just say to have me 'google it.' I've been working on this for a couple days now and I thought it's about time to ask someone who perhaps dealt with the same problem.

Thanks in advance.

[spaceminer143]

I believe that you can make this query work by using a dollar sign and single quotes:

grep -l $'\xFF\xD8\xFF' ./*

Enjoy!

[mattseanbachman]

Oh man, thanks a bunch. I never thought to try that because as I believe the texts on the matter dictate, $ is an end of line. But it works!!