Finding a number in a .txt file

[q-bertsuit]

Hi!

I'm trying to grab som info that is spat out when I run a certain command. I'm doing this in a script..

At the moment I'm putting the output in a text file, output.txt and I'm trying to analyze it in the next commands.

So, if I run:
ListInfo > output.txt

The number I need to catch in the textfile will sort of look like this:

Lots and lots of information
-
-
-
THIS_IS_THE_FIRST_STRING_IM_LOOKING_FOR
Something: Foo
SomethingElse: Bar
THIS_IS_THE_SECOND: 045 <--Number I want

My question is; how can I search through output.txt, look for the first string, get the third after that, and extract the last three characters (three digit number) at the end of the line?

Can this be done without first saving to a txt file?

Not sure if that made sense at all..

Thanks alot for your help!

[gaurav-joseph]

you could try

listinfo | grep THIS_IS_THE_SECOND | tail -c -4

the last char is null or newline i don't know which

[tpb261]

listinfo | grep -A 4 THIS_IS_THE_FIRST | tail -c 4
idea:
grep: use context
tail: print last "N" bytes

eg:

$ echo "Lots and lots of information
-
-
-
THIS_IS_THE_FIRST_STRING_IM_LOOKING_FOR
Something: Foo
SomethingElse: Bar
THIS_IS_THE_SECOND: 045" | grep -A 4 THIS_IS_THE_FIRST_STRING_IM_LOOKING_FOR | tail -c 4    <return>
045

[cnamejj]

I'm starting to feel like I'm the AWK pimp on this website, but it's really well suited for this sort of scripting. So assuming you want to do the following,

- parse the output from the command "ListInfo"
- search for "THIS_IS_THE_FIRST_STRING_IM_LOOKING_FOR"
- once you find that, search for "THIS_IS_THE_SECOND"
- print the last word on that line
- then ignore the rest of the output

then this command line might help.

ListInfo | awk '/THIS_IS_THE_FIRST_STRING_IM_LOOKING_FOR/ { trigger = 1; } trigger && /THIS_IS_THE_SECOND/ { print $NF; trigger = 0; }'

If you really want the last three character of the line then replace "$NF" with "substr($0,length($0)-2" in the command line.