Ok now I almost have it, but not quiet..

[cdslaughter]

Ok look at the following file

test.file

1  9199=4p
121   JOHN.tmp   DALLAS   09/10/07
#
     1 - Create files
     2 - Convert Times
     3 - Calculate time
          1 - Compute regular time
          2 - Compute Otime
     4 - Verify vacation


Completed steps ______
1  9199=4p
121  MIKE.tmp   DALLAS  09/10/07
#
     1 - Create files
     2 - Convert Times
    

Completed steps ______
1  9199=4p
121   MARY.tmp   DALLAS   09/10/07
#
     2 - Convert Times
     3 - Calculate time
          1 - Compute regular time
          2 - Compute Otime
     4 - Verify vacation


Completed steps ______

Ok I need to pull portions of this file out and save them as variables in a script. (CSH)
I want to be able to pull the name ($name) location ($location) and date ($today). Then store the steps for each person in a variable to be displayed later.

Here is an example of the desired output.

09/10/07
---------------------------------------------------------------------------
Dallas  |  1  |  2  | 3.1 | 3.2 |  4  |

JOHN    |  Y  |  Y  |  Y  |  Y  |  Y  |
MIKE    |  Y  |  Y  |  -  |  -  |  -  |
MARY    |  -  |  Y  |  Y  |  Y  |  Y  |

I am fairly sure this can be done with "grep", "awk" and or "sed", But I am un sure of how to go about it.

I know if I do something like

cat test.file |grep 121 | awk 'set $name = $2'

(my syntax may be a bit off, but I am still learning) it will dump the John then mike then mary to the variable $name. However this does not nelp me much. Also keep inming that the name "Jonh, Mike, Mary ect..." will change on a daily basis and not necessarly be in the same order or always have the same steps everytime I run the script.

Any input would be greatly appreciated..

Thanks

Carl

[cdslaughter]

Ok looking into this further all I really need to do is do something like this:

Grep read line 1 of test.file > $thisline
if (first 3 spaces of $thisline = 121) then
awk $thisline '
[print $2}' > $name
else
if (first 5 spaces of $thisline = " ") then
thave what is found in 6th space to $a
Else
...

And so on.. Just not sure how to make grep read a file 1 line at a time.

Thanks

Carl

[cdslaughter]

Com'on anyone have an Idea here??

This cant be THAT hard..

It is simple How do I get my script to read a file one line at a time?

#! /bin/csh
# test file name is X.FILE

set thisfile = `wc -l X.FILE | awk '{print $1}'`
set line = 1
While ($line !> $thisfile)
  Read $line of X.FILE
      if ()then
      Else
      endif
      inc $line
  (Go back, read line 2, and repete till end of file) 
end

To be honist I just need help with this line:

 Read $line of X.FILE

I really would appreciate any help.

Carl

[jozyba]

....How do I get my script to read a file one line at a time? ....

If you're determined to use csh you might get more help on the BSD forums, although I think most of them are moving to bash now.

#! /bin/csh 
# This works with csh and tcsh

set length = `wc -l X.FILE` 
set counter = 1 

while($counter <= $length[1]) 
    set line = `head -$counter X.FILE | tail -1` 
    echo "$line"
    @ counter++ 
end

#! /bin/bash 
# This works with bash, dash, ksh, and zsh

while read line; do
    echo "$line"
done <X.FILE

[chrism01]

Yep, that should enable you to read the file 1 line at a time.
You can use
rslt=`echo $line|grep <pattern>`
to check for each string