gcc -DDEBUG option

[rabantu]

Hi Gurus,

I have a quick question. I am supposed to implement a Debug trace when my project is compiled with gcc -DDEBUG option.

I declared a macro as such:

#ifdef _DEBUG
#define DEBUG_TRACE(x) printf("%s\n", (x))
#else
#define DEBUG_TRACE(x)
#endif

Then in my code, I am using the DEBUG_TRACE macro. However, I am not outputiing my debug statements wven after compiling with the gcc -DDEBUG option. Can someone please point me what am I doing wrong?
PS: I tried different options like just DEBUG etc. with no avail.

-Thanks in advance
rabantu

[wje_lf]

You have two choices.

First, you can compile with this:

gcc -D_DEBUG

But a better choice is to do this:

#ifdef DEBUG     /* not _DEBUG */

The reason is that in C you should avoid using identifiers that begin with an underscore, to avoid collision with identifiers used by those who implement the compiler.

Hope this helps.