How to find Date format and extract line??

[cyberray]

Hi guys,i got this problem which is..i need to find those sentences with date inside and extract them out,the input is somehow like this

eg:
$DATA42.GANTRY2.GA161147 DISKFILE 2007-10-16 11:56:45 SUPER.OPR \NETS.$Y4CB.#IN
\NETS.4,246
F DENIED READ

Report date range........: 2007-08-01 00:00 to 2007-08-01 23:59
Subject System...........: *
Subject Userid...........: *.*
Subject Login Name.......: *
Subject Terminal.........: *
Operation................: *

so what i need is the one with the date format (yyyy/mm/dd):
$DATA42.GANTRY2.GA161147 DISKFILE 2007-10-16

this line will be printed..can this be done using sed or awk????

[Franklin52]

Something went wrong see below:

[Franklin52]

Try this, it prints the 3th field of the line if the first field match with the regexp:

awk '$1 ~ "\$DATA42.GANTRY2.GA161147" {print $3}' file

Regards

[cyberray]

Hi Franklin,well..the above code i post is not only the file that i need to find the sentences,so i was wondering that if sed or awk can find all those sentences with data format and extract them?Is there anyway to do it?

[Franklin52]

Not really clear for me what you're trying to achieve.
Can you provide further information e.g. the format of the file and the expected output.

Regards

[cyberray]

hey franklin,thanks for replying,i found the answer le,but thanks to your previous code also,thanks alot!