simple bash question

[djcham]

Hi all,

I'm trying to figure out how to loop a variable inside a variable and print it out. Here is the example

for ((i=1;i<=4;i+=1)); do
echo $var$i
done


I can accomplish what I did above by:

echo $var1
echo $var2
echo $var3
echo $var4

I've tried many different ways to get this to work to no avail. Any suggestions?

Jon

[wje_lf]

We pretty much thrashed that to death here.

[djcham]

thanks. so the answer is that you have to use arrays?

[wje_lf]

No, you probably don't have to use arrays, but that's the best way to write maintainable code.

If you don't want to use arrays, there's a suggestion in that thread about eval.