How to get the Filename in .awk running on Linux

[mkapadia]

I need to migrate some scripts running on SunOS to Linux,
script running on SunOs used to get the filename that was passed as a paramenter to the .awk script as

outFile=substr(FILENAME,1,3)

the problem is variable FILENAME does not work on Linux, is ther any other alternative?

thanks in advance for the help.

[coopstah13]

$1 is first parameter passed to a shell script

[mkapadia]

its an awk script not shell, the command is
awk -f compareSum.awk prod.dat test.dat

and I need to get prod.dat into some variable.

[drl]

Hi.

It works for me in this situation:

#!/usr/bin/env sh

# @(#) a1       Demonstrate variable FILENAME in (g)awk.

set -o nounset
echo

## Use local command version for the commands in this demonstration.

echo "(Versions displayed with local utility \"version\")"
version >/dev/null 2>&1 && version bash awk

echo

# Use nawk or /usr/xpg4/bin/awk on Solaris.

echo " Hello, world." > t1
awk '
        { print
          print " Currently reading FILENAME", FILENAME }
' t1

exit 0

Producing:

% ./a1

(Versions displayed with local utility "version")
GNU bash 2.05b.0
GNU Awk 3.1.4

 Hello, world.
 Currently reading FILENAME t1

The man page may be of value ... cheers, drl

[mkapadia]

is this working on Linux?, variable FILENAME is working for me on SunOS but not Linux.

[patch_linams]

Well, here is one example how to do it in your compareSum.awk:

#!/usr/bin/awk -f

BEGIN {}
{
    print FILENAME;
}

As you can see, FILENAME works just fine

[mkapadia]

doesn't work on Linux, works on Solaris.

[patch_linams]

And I thought I was running Linux on all my machines...

Execute this on your computer and post here the result:

uname -a
awk --version | head -1

What Linux distribution do you use?

[mkapadia]

uname -aLinux enycxapramaps017 2.6.9-22.0.2.ELsmp #1 SMP Thu Jan 5 17:11:56 EST 2006 x86_64 x86_64 x86_64 GNU/Linux


awk --version | head -1
GNU Awk 3.1.3

[patch_linams]

It has to work on your system. Try this one (although it's not preferable):

#!/usr/bin/awk -f

BEGIN {}
{
    print ARGV[1];
}