how to replace a line of code something like grepreplace maybe??

[samf]

I know how to do grep, that's very nice.

But I want to search a folder and it's subfolders and REPLACE a line of code in a file, e.g.

this line

if($qr['count']>1){

with this one

if($qr['count']>1 && !$usemod_settings['allowDuplicateEmails']){



How do you do that in linux?
Thanks,
Samuel

[Ogion]

You can do that with sed.

The syntax shouldbe something like
sed s/pattern/itsreplace/[Mode] file
Look in the manpage for the details, since i didn't used that before...

Ogion

[FunkyRes]

Use sed >= 3.95 so you can edit the files directly with -i switch.

IE -

sed -i 's?old string?new string?g' /path/to/file

if you have a whole directory - somethiling like

find /path/to/directory -type f -print |while read file; do
sed -i 's?old string?new string?g' "${file}"
done

would work.
Of course back up the directory first.

I always use a ? instead of / as a delimiter so I don't have to escape the / character in the expression.

[ghostdog74]

if you know the file names

sed -i 's/cat/dog/' file*.sh

for one directory level

sed -i 's/cat/dog/' */file*.sh

[scm]

I always use a ? instead of / as a delimiter so I don't have to escape the / character in the expression.

I usually use the pipe symbol (|) since that looks (to me) a more natural separator than a question mark, although pretty much any appropriate punctuation character can be used.