UNIX script help

[ebahti]

I wrote this script , but it didn't work.It must find a specific example in a specific file using grep command entered by the user,but the file and example are like variables entered in the shell promt,not declared in the script.
it must look like this ./scriptname 'word or something' filename

#!/bin/bash 
OK=0 
   FILENAME=$1 
   WORD=$* 
if [ $? -eq $OK ] 
then 
grep $FILENAME | while read $FILENAME 
   do 
      grep -in "$WORD"   $FILENAME 
done 
else 
echo "$WORD not found in $FILENAME" 
fi 
exit

[anomie]

There are some obvious problems with the script. To spot them, run it with the debugger, e.g.:
bash -x ./script_here arg1 arg2

You can watch what values are really getting assigned to variables and troubleshoot from there.

If you don't already know about it, the Advanced Bash Scripting Guide on tldp is a good reference.

[ebahti]

I still don't get it.I wrote something else:

#!/bin/bash
OK=0
word=''
filename=''
for filename
do grep -in "$word" "$filename"

if [ $? -eq $OK ]
then
echo "$word found in $filename"
else
echo "$word not found in $filename"
fi
done
exit 
and the debugger said:
 bash -x ./new.txt 'just' news.txt
+ OK=0
+ word=
+ filename=
+ for filename in '"$@"'
+ grep -in '$word' '$filename'
grep: $filename: No such file or directory
+ '[' 2 -eq 0 ']'
+ echo ' not found in just'
 not found in just
+ for filename in '"$@"'
+ grep -in '$word' '$filename'
grep: $filename: No such file or directory
+ '[' 2 -eq 0 ']'
+ echo ' not found in news.txt'
 not found in news.txt
+ 'exit$'
./new.txt: line 14: exit$: command not found

something must be done ,but what ?

[anomie]

You still need to read the scripting guide I pointed you to. Particularly the section about positional parameters.

Using the debugger to figure out what's happening with your script at runtime is a good practice.