trouble with sscanf

[MrUmunhum]

Hi group,

I am fighting with sscanf again. I am trying to use the pointer update
feature "%p" and it is not working as expected.

The code looks like this:

int
main( int argc, char* argv[] ) {

int RC=0;

int I1,I2,I3,I4;
char* _P;
char Buffer[] = "1\n2\n3\n4\n xxzzy The rest of this ! \n";
char Temp[255];

strcpy(Temp,Buffer);
_P = Temp;

RC=sscanf( _P, "%d\n%d\n%d\n%d\n%p", &I1, &I2, &I3, &I4, _P );
printf( "RC = %d %d %d %d %d New=%s\n\n", RC, I1, I2, I3, I4, _P );

strcpy(Temp,Buffer);
_P = Temp;

RC=sscanf( _P, "%d\n%d\n%d\n%d\n%s", &I1, &I2, &I3, &I4, _P );
printf( "RC = %d %d %d %d %d New=%s\n\n", RC, I1, I2, I3, I4, _P );

return;

The output looks like this:

RC = 4 1 2 3 4 New=1
2
3
4
xxzzy The rest of this !


RC = 5 1 2 3 4 New=xxzzy

What I am trying to do is update the pointer to the data after the
conversion so that _P pointers to "xxzzy The rest of this !"

Any ideas?

[wje_lf]

Format %p in sscanf() is not a pointer update feature. It attempts to read the value of some pointer from the input. The closest to what you want is the %n format.

Hope this helps.

[MrUmunhum]

Format %p in sscanf() is not a pointer update feature. It attempts to read the value of some pointer from the input. The closest to what you want is the %n format.

Hope this helps.

Bill,
Thanks for the reply. Using '%n' is what I did use. Not pretty but it works!
William