bash/C issue

[supawolo]

Suppose I compile the following simple program to count the number of chars in an input:

#include <stdio.h>

main()
{
long nc;

nc = 0;
for (nc = 0; getchar() != EOF; ++nc)
;
printf("%1d\n",nc);
}

Now, when I run this program from bash (with ./a.out), I can input, but for some reason the output never comes. The output does come, however, when I put the printf statement inside the loop. Does anyone know how to resolve this issue?

Thanks!

[gerard4143]

Try ending your program with Ctrl-D, which is EOF

[supawolo]

thanks, it works

[gerard4143]

That's to say when your program is running terminate it by typing Ctrl-d, this will put EOF in the input stream so when getchar retrieves it getchar() == EOF and your program will end