Help with Shell Script

[xrserver]

Ok well I am very new to shell scripting. I have a script which I want to check the server load and if it is above a certain number it should wait X number of seconds before continuing. Right now this all thats in the script but I have another script I wrote which i will be putting this in.

I keep getting this error and as I said I am very new so I do not know really how to fix it.
line 4: [: 0.20: integer expression expected

This is my script so far

#!/bin/bash
load=`awk '{print $1}' /proc/loadavg`
echo $load
if [ $load -gt 1 ]
then
cool='200'
echo "Server load is above 1, cooling down"
time='0'
while [ $time != $cool ]
do
time=`expr $time + 1`
done
else
echo "Server Load is $load no need to cool down"
fi

Any help will be greatly appreciated.

[i92guboj]

Ok well I am very new to shell scripting. I have a script which I want to check the server load and if it is above a certain number it should wait X number of seconds before continuing. Right now this all thats in the script but I have another script I wrote which i will be putting this in.

I keep getting this error and as I said I am very new so I do not know really how to fix it.
line 4: [: 0.20: integer expression expected

The load average is expresed as a number with decimal cyphers. Bash built in arithmetics can only handle integers. If you only care about the integer part, you can just discard the rest.

awk -F "." '{print $1}' /proc/loadavg

There's no need to use awk in bash, though.

var=$(< /proc/loadavg)
var=${var/.*/}

Also, you assume that each iteration in the while loop will last 1 second. That's not true. Read about the sleep command.

sleep 200

Would suffice.

[ghostdog74]

try this construct instead. you use the math inside awk to do the number comparison

load=$(awk '$1 > 1 { print "overload" }' "/proc/loadavg")
if [ $load == "overload" ];then
 echo "cooling down"
 sleep 200
 # code
fi