How print Last String of the Line in Shell

[jaigs_27]

I have a file like in following format

Hello:World universe
Hello world universe hello
Hello world universe:hello
hello universe hello world hello
universe hello world

now I want to print last <string> of all lines, is there any way??
universe
hello
universe:hello
hello
world


thanks

[Kieren]

Yes, it's quite simple using awk:

awk '{ print $NF }' <filename>

Where <filename> is replaced with your file

[jaigs_27]

Thanks, now I am facing some problem, if u can help me.

i am getting trailing line, how can I remove that, see below

$test = ssh hostname cat /proc/cpuinfo |grep -i 'model name'
echo "$test"

(standard input):model name : Intel(R) XEON(TM) CPU 2.40GHz
<trailing line>

And when I am checking value in variable, nothing is there

if [ -n $test ]; then
echo "$test"
else
echo "Error"
fi

but nothing is happening, even else is also not executing

[Kieren]

You need to use some quotes. Try:

$test = `ssh hostname cat /proc/cpuinfo |grep -i 'model name'`
echo "$test"

The quotes I've used can be found by using shift and the key above the tab key.

[chochem]

I have a file like in following format

Hello:World universe
Hello world universe hello
Hello world universe:hello
hello universe hello world hello
universe hello world

now I want to print last <string> of all lines, is there any way??
universe
hello
universe:hello
hello
world


thanks

I believe grep could do it with:

 grep -o -E -e '[^ ]+$' <filename>

Not that it's any easier to read, mind you...