bash redirection

[e404]

Program A calls program B
I redirect A's output to program C
What to do to see B's output on the screen rather than pipe it to C?

I write A and C
B is external

B needs input, so I cannot pipe all B's output to C and make C writing B's output on the screen.

[Cabhan]

Why not have A call B first, then redirect its output to C, then call C?

Basically, a child process inherits the redirections of its parents, so once you've redirected A somewhere, there's no safe way to get B back to the terminal.