need regex to return version information only

[craftereric]

I am using gawk and need a regular expression that will return the version information ONLY.

My input file is the following:
xline 1
xline 2
3.3.6.4
the next line 4.2.45.3 is here

I want to return:
3.3.6.4
4.2.45.3

My current expression:
awk --re-interval '{
for(i=1;i<=NF;i++) {
if ( $i ~ /^([[:digit:]]{1,3}\.){3}[[:digit:]]{1,3}$/ ) {
print $0
}
}
}' "file"

returns
======
3.3.6.4
the next line 4.2.45.3 is here

What is missing?

[eggi]

Hey There,

The basic issue is that you're printing out $0 (the entire line) when your pattern matches.

I'm sorry I don't the syntax for carrying over your match and only printing that for gawk, but if you can figure that out, it's the only problem

Best wishes,

Mike

[ghostdog74]

you are going over the fields, so just change print $0 to :

print $i