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hi
am compiling the simple code below about encryption
#include <stdio.h>
#include <time.h>
#include <unistd.h>
#include <crypt.h>
int
main(void)
{
unsigned long seed[2];
char salt[] = "$1$........";
const char *const ...
- 04-25-2008 #1Just Joined!
- Join Date
- Mar 2008
- Posts
- 23
Crypt function problem
hi
am compiling the simple code below about encryption
#include <stdio.h>
#include <time.h>
#include <unistd.h>
#include <crypt.h>
int
main(void)
{
unsigned long seed[2];
char salt[] = "$1$........";
const char *const seedchars =
"./0123456789ABCDEFGHIJKLMNOPQRST"
"UVWXYZabcdefghijklmnopqrstuvwxyz";
char *password;
int i;
/* Generate a (not very) random seed.
You should do it better than this... */
seed[0] = time(NULL);
seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
/* Turn it into printable characters from `seedchars'. */
for (i = 0; i < 8; i++)
salt[3+i] = seedchars[(seed[i/5] >> (i%5)*6) & 0x3f];
/* Read in the user's password and encrypt it. */
password = crypt(getpass("Password:"), salt);
/* Print the results. */
puts(password);
return 0;
}
but it s giving the following error: "Crypt.c
.text+0x100): undefined reference to `crypt"
what might be the problem? any help will be gladly appreciated
thanks
- 04-25-2008 #2
From the man page:
Hope this helps.Programs using this function must be linked with -lcrypt.--
Bill
Old age and treachery will overcome youth and skill.
- 04-25-2008 #3Just Joined!
- Join Date
- Mar 2008
- Posts
- 23
Thanks a lot for ur help....it worked


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