Find directory-size through C ??? LINUX ???

[rafian512345]

Hey guys !

You know, I've been working hard the whole day trying to figure out
one damn system-call or library function that could tell me the
accurate size of any directory (with its contents) anywhere in a
filesystem.

Believe me, I've pestered every book, web-page, and any reference
on Linux programming that I could.
And I now have an idea that there actually isn't any such library
function or method (IN C/C++).

Also, so far as I know, a directory's size is NOT simply a summation of its constituent files.

So, can you please help me calculate the directory-size through a pseudo
code or a ready-made C code (I'll kiss you for that! (on your head)).

HELP !!!

[wje_lf]

Kisses or no, you can get the size of the directory itself (not including its constituent files) by calling stat() on the directory and multiplying together the st_blksize and st_blocks fields of the resultant struct stat.

You can do exactly the same thing for each of the constituent files. If any of those is a directory, do the same thing for each of its constituent files, and so on.

Then add it all up.

As I'm sure you know by now, opendir(), readdir() (the one in section 3 of the man pages, not section 2), and closedir() are what you use to step through a directory. Skip the . and .. entries in each directory.

I won't waste my time or insult your intelligence by actually writing the code, but that ought to be all you need.

I just got a kiss from my wife (on the head), so that about wraps this up!

Hope this helps.

[rafian512345]

Thanks Bill !
You're a nice pal.

[gerard4143]

Not sure if this is what your looking for, but try:

du -a directoryname

[rafian512345]

Not sure if this is what your looking for, but try:

du -a directoryname

Thanks for your concern, Gerard,
but I was actually looking for a method in C language,
and not a command.
But I think, if I look into the implementation of this 'du',
I might find a way out.

Thank you once again.

[abhi_oldfort]

Hello,

Well, i need to know the size of the directory and also the last modified date of the directory. So can u please help me with the script.

It will be very helpful


Thanx and Regards
Abhishek.

Kisses or no, you can get the size of the directory itself (not including its constituent files) by calling stat() on the directory and multiplying together the st_blksize and st_blocks fields of the resultant struct stat.

You can do exactly the same thing for each of the constituent files. If any of those is a directory, do the same thing for each of its constituent files, and so on.

Then add it all up.

As I'm sure you know by now, opendir(), readdir() (the one in section 3 of the man pages, not section 2), and closedir() are what you use to step through a directory. Skip the . and .. entries in each directory.

I won't waste my time or insult your intelligence by actually writing the code, but that ought to be all you need.

I just got a kiss from my wife (on the head), so that about wraps this up!

Hope this helps.