Need help with a script..

[djfog]

Hi to all.I have this script:

#!/bin/bash
awk -F: '{print $1 "\t" $6}'</etc/passwd

and I want to modify it so that it will print only the login names and the home directories of the users that are currently logged in the system.
Thanks in advance..

[bigtomrodney]

You might want to combine this with the who command. The who command will tell you who is online now. So something that would parse the logged on users then check them against /etc/passwd

for loggedin in $(who |awk '{print $1}'
do grep $loggedin /etc/passwd |awk -F:'{print $1 "\t"$6}'
done

That's just rough syntax, you will need to test that yourself. The logged in variable is set as the first token from each line returned by the who command, i.e. the username. This is then grep'd in /etc/passwd and your awk filter is then applied.

[djfog]

Yeap.That's exactly what I need.But now all I need is help with the syntax.
Please..

[ghostdog74]

just awk

awk -F":" 'BEGIN{ "who -q" | getline line}
{ user[$1]=$6 }
END {
  n=split(line,l," ")
  for(p=1; p<=n; p++ ) {
   print l[p],user[l[p]]
  }
}' /etc/passwd

[djfog]

Thanks my friend.It works like a charm.It is exactly what I need.

[bigtomrodney]

just awk

awk -F":" 'BEGIN{ "who -q" | getline line}
{ user[$1]=$6 }
END {
  n=split(line,l," ")
  for(p=1; p<=n; p++ ) {
   print l[p],user[l[p]]
  }
}' /etc/passwd

That's tidy ghostdog. I think I'll need to read up more on awk!