Get output of a command

[zn0wm4n]

Hello,

I have never made a bash script in my life, so i need some help.

I want a script thats taking the output of an command and use it in a other command.

somthing like:

$command1 = 'uptime'

$command2 = 'customcommand'

and then the it will be put thogeter and run

$command2 $command1.

Do you understand?

[Lakshmipathi]

Use pipe command .

pipe command redirects output command-1 as an input for command-2

Example:

$ls | more

output of ls command is the input for more command.

For more click here
Pipeline (Unix) - Wikipedia, the free encyclopedia

[wje_lf]

If you want to take the output of one command and make that the input of another command, and these two commands have been assigned to variables, do this:

command1='uptime'
command2='customcommand'
$(command1) | $(command2)

[zn0wm4n]

Okay, think thats what im after, but the last command must be in "" When its outputted after the first, how do i do that?

[wje_lf]

Okay, think thats what im after

Are you talking about the solution offered by Lakshmipathi, or the one offered by wje_lf?

the last command must be in "" When its outputted after the first, how do i do that?

I have no idea what you're asking here. Could you illustrate with an example or something?

[zn0wm4n]

Your example.


Okay, im not god to explain but ill try,

command1='uptime'
command2='customcommand'
$(command1) | $(command2)

the last output of everything should be:

comstomcommand [options to this command] "uptime"

or

#comstomcommand -s  "22:47:07 up  2:21"

[zn0wm4n]

I got it working Thanks for the guide lines!


The code for getting command2 after command1 in qoutes:

command1='uptime'
command2='customcommand'
$command2 "`$command1`"