c programing with linux command!!

[slackman]

#### test.c#####

#include <fcntl.h>
#include <string.h>
#include <sys/stat.h>
#include <sys/types.h>
#include <unistd.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <sys/ioctl.h>
#include <netinet/in.h>
#include <net/if.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>

int main(int argc, char **argv )
{

if(strcmp(argv[1],"mac_arp")==0)
{
system("/usr/local/bin/naxclassv2 access arp -en | grep $1 | awk '{print $3}'");
}

}

i use c programing for call system command on linux fedora and how to call argv ($1) for filter mac address


test mac_arp 172.168.1.200
result it's show mac address of 172.168.1.200

i can try this it's not working. please help me

[tpl]

are you calling your program "test"?
the problem is, /usr/bin/test will be run,
unless you say "./test" or else use another
name

[slackman]

are you calling your program "test"?
the problem is, /usr/bin/test will be run,
unless you say "./test" or else use another
name

no no!! i can call test it working. but argv include not working.

[gerard4143]

in your if statement try:

if(!strcmp(argv[1],"mac_arp"))

I think this is what you want

[wje_lf]

in your if statement try:

if(!strcmp(argv[1],"mac_arp"))

I think this is what you want

No, that won't change the behavior of his program.

[gerard4143]

Ooops...Gerard