awk capture column 2 to the end

[raphi078]

hello users

I use this syntax in a bash-script on kubuntu:

ls -lah --sort=size `cat $LOGFILE.tmp` | awk '{print $5 " " $8}' > $LOGFILE

now, the problem is, if a filename (usualy in $ has a space inside, then the rest of the name is in $9 etc...

how can I say, and now from $8 to the Lineend?

thank you.
raphael

[secondmouse]

Use $NF to refer to the last column,
ls -lah --sort=size `cat $LOGFILE.tmp` | awk '{print $5 " " $NF}' > $LOGFILE

[raphi078]

hmm, not exactly, what I mean.

if I have this situation:

logfile:
75k /home/user/Text-File1.txt
72k /home/user/Text-File2.txt
78k /home/user/Text File3.txt

notice the "space" in the third line!


then process through:
cat logfile | awk '{print $2}'

then the third line is only: "/home/user/Text"

and not the exact Filename... how can I change that?

[ghostdog74]

if you have Python

#!/usr/bin/env python
for lines in open("logfile"):
    lines = lines.strip().split(" ",1)
    filename = lines[1]
    size = lines[0]
    print filename,size

[scm]

Use cut (and not cat!)

cut -d" "  -f2-  logfile

[secondmouse]

If all filenames starts with "/", you can use awk like this:
awk 'BEGIN{FS=" /"} {print "/"$2}' logfile