1 Line script syntax problem

[sgunners]

trying to do something very basic but having a very difficult time.

assuming the following:

date | awk '{print "'\''"$2,$3"'\''"}'

will return
'Oct 07'

and

ls -ltr | grep `echo com`

will return
-rw------- 1 ??????? ????? 2440 Jul 06 19:15 commands.txt

Why is it that I cannot combine them both to list and grep by 'Oct 07'?

ls -ltr | grep `date | awk '{print "'\''"$2,$3"'\''"}'`

returns
grep: 0652-033 Cannot open 7'.



I just realized even if I did get this script's syntax correct it would not work as date returns Oct 7 and when doing ls -ltr the date is displayed as Oct 07

[smolloy]

This is because the "date | awk ..." command returns two words -- Oct 07, so grep tries to grep the file "7" for the word "Oct". Perhaps if you put the date command in double-quotes

ls -ltr | grep "`date | awk '{print "'\''"$2,$3"'\''"}'`"

I have no idea if that'll work, but you could give it a try....

Welcome to the forums

[secondmouse]

If you are trying to list files/folders modified within less than 24 hours started from 00:00 today, try to use command find instead:
find . -daystart -ctime -1 -exec ls -l {} \;

Or if you still want to use ls and grep, try
ls -ltr | grep "`date '+%b %d'`"