getting value of a variable which consists of a variable again like ${${}}

[sandeep t]

I have a file consisting of variable definitions like:

NoOfInstTypes=2
Inst.Type1="Server"
Inst.Type2="Client"

I want to get the value of Inst.Type variables in a loop.
so, I do this

NoOfTypes=$NoOfInstTypes
while [ $NoOfTypes -ne 0 ]
do
Type=${Inst.Type$NoOfTypes}
..
..
NoOfTypes=`expr $NoOfTypes -1`

But this gives syntax error.

[burschik]

var1=hello
index=1
eval echo \$var$index

You might also consider using an array.

[wje_lf]

burschik's idea might work, but you'll probably also benefit by looking at corrections to your original script.

One of them, you'll notice, is the use of underscores instead of periods.

Hopes this helps.

#!/bin/bash

NoOfInstTypes=2
Inst_Type1="Server"
Inst_Type2="Client"

NoOfTypes=$NoOfInstTypes

while [[ $NoOfTypes -ne 0 ]]
do
  Type=Inst_Type$NoOfTypes

  echo Type is $Type

  NoOfTypes=$(($NoOfTypes -1))
done

[vsemaska]

You'll need to change:

Type=Inst_Type$NoOfTypes

to:

eval Type=\${Inst_Type$NoOfTypes}

in order to get the value of the variable.

[wje_lf]

Correct. My bad.