How to take the difference in minutes and seconds

[packet]

Hello All ,

The below code will give the time difference between two times as defined . and it will give as shown below .
this code is written by some one else ... this is working fine but my requirement as follows

13:00:00
14:00:00

the present code will give the output 01:00:00 differnce but i need it has difference of 60 minutes and also second of 3600

how i have to modify this code ? or How i have to write code ?

please help me out ....

#variables
#ft% are from the first time
#st% are from the second time
#dt% difference time

#cut out the hours minutes seconds

fth=`echo "$ft" | cut -c1-2`
ftm=`echo "$ft" | cut -c4-5`
fts=`echo "$ft" | cut -c7-8`
sth=`echo "$st" | cut -c1-2`
stm=`echo "$st" | cut -c4-5`
sts=`echo "$st" | cut -c7-8`



# do the math for seconds

dts=`expr $sts - $fts`
if [ $dts -lt 0 ]
then
	dts=`expr $dts + 60`
	ftm=`expr $ftm + 1`
fi
for val in $dts
do
	if [ $val -lt 10 ]
	then
		dts=`echo "0$val"`
	else
		dts=`echo $val`
	fi
done



# do the math for minutes

dtm=`expr $stm - $ftm`
if [ $dtm -lt 0 ]
then
	dtm=`expr $dtm + 60`
	fth=`expr $fth + 1`
fi
for val in $dtm
do
	if [ $val -lt 10 ]
	then
		dtm=`echo "0$val"`
	else
		dtm=`echo $val`
	fi
done



# do the math for hours

dth=`expr $sth - $fth`



# put dtime back together

difftime=`echo $dth:$dtm:$dts`

[burschik]

Are you serious? The variables $dth, $dtm, $dts already contain all you need to know. The difference in seconds is $dth * 3600 + $dtm * 60 + $dts, for example.

[packet]

sorry ... I just forgotten to convert ...!!! thanks for remembering..!!!