How to take the files from a directory and remove after process

[packet]

Hello All,


I am writing script in bash as follows

-> I have to take a files ( Image files .jpeg) from a directory ( source directory ) one by one
-> cut the file in to 3 parts
-> remove the middle part and store the 2 parts in another directory ( destination directory )
-> after cut remove the file from the source directory
-> it has to do for all the files in a source directory .( assume 100 files )

assume source directory as 100 files

the following the code i written I dont kow how to continue?

please help me out

#!/bin/sh

#take the file from source directory

var=`ls -t /home/sud/desktop/jpeg | head -n 1`

#cut the image into 3 parts

convert -crop <Dimension> soursefile.jpeg destinationfile.jpeg

problem is how to make loop and how to delete one of them in 3

because cut files are stored in a destination directory in a order - filename-0.jpeg ,filename-1.jpeg filename-2.jpeg

i have to remove filename-1.jpeg

thanks in advance

[creepy cripple]

I assume when you want to cut the file in 3 parts you mean to store the content of the file in 3 different files

#!bin/bash

cd $source_directory

for myfile in * #all your files in source_directory will be processed!
do
#somehow get the 3 parts from the file being processed
$file-0.jpeg=...
$file-1.jpeg=...
$file-2.jpeg=...
#copy interesting parts to destiny_directory (the parts should be files)
cp ./$file-0.jpeg $destiny_directory
cp ./$file-2.jpeg $destiny_directory
rm $myfile
done

NOTE: take care not to store this script in source_directory, it would be wiped out by the for loop