Script to kill a process

[emp1953]

I am writing a script that needs to get a pid for a process
I'll use pidof() for that
Then I have to kill the process and everything associated with it.
So I must do a "kill -9 pidof()" ........
But the syntax will not work that way.

Any suggestions on how to accomplish this?

Thanks

emp

[wje_lf]

With the bash shell, putting something in $(...) means that the part between the parentheses is to be executed as a shell command, and the output is to be placed at that point in the overall line.

Example:

ls -t

lists the names of the non-hidden files in the current directory, sorted by time of most recent modification, so the files which have been modified most recently appear at the beginning.

ls -t | head -1

lists the name of the single most recently modified non-hidden file in the current directory.

head -5 $(ls -t | head -1)

displays the first five lines of that file.

pidof fred

will get the pid of the process(es) running a program named fred.

pidof -s fred

does the same, but also includes any instance of bash which is running a script by that name. If you're trying to kill a bash script, you'll want the -s option.

kill -9 $(pidof -s fred)

should do what you want.

Hope this helps.

[burschik]

You might also try "pkill".

[wje_lf]

Quoth the highly esteemed burschik:

You might also try "pkill".

Absolutely correct. I had no idea that pkill even existed.

emp1953, if you read the man page for pkill, you'll discover a collection of options available for it. Most of them probably won't interest you, but a few of them might.

Worth checking out.

[emp1953]

The "-s" option was the missing part of my puzzle.

Things are working the way they should be.