problem of cutting last two characters..!!!!

[packet]

Hello All,

I am getting one basic problem of cutting last characters in a file name please help me out

the following is the code

#!/bin/sh

file=`ls -t /home/directory | head -n 1 `

echo $file

output - tr06_2008-11-04_12-09-09_657.34M.jpeg-0


Now my problem is I want to remove the last two -0 character from the file name

there in proper length in tr06 i.e it may vary to tar0006 or tar000008 etc and 657.34M it also varies but the date and time are constant .



so i want = tr06_2008-11-04_12-09-09_657.34M.jpeg




how ?

please help me out ?

[secondmouse]

$file=${file%-0}
should give you what you need.

[wje_lf]

$file=${file%-0}

doesn't seem to work. I tried this:

#!/bin/bash

file=abcdefgh
echo $file
$file=${file%-0}
echo $file

and got this output:

abcdefgh
/tmp/w1: line 5: abcdefgh=abcdefgh: command not found
abcdefgh

bash got confused because of the assignment to $file, which should have been an assignment to file. So I ran this instead:

#!/bin/bash

file=abcdefgh
echo $file
file=${file%-0}
echo $file

and got this output:

abcdefgh
abcdefgh

Not exactly what we wanted, but at least the error message went away.

I'm not sure what you intended with the percent sign, secondmouse, so I just looked at the bash documentation and came up with this:

#!/bin/bash

file=abcdefgh
echo $file
file=${file:0:${#file}-2}
echo $file

... and the output looked like this:

abcdefgh
abcdef

So that's how to strip off the final two characters of the content of a bash variable.

Hope this helps.

[drl]

Hi.

For the specific case of dash-digit, this can be done:

#!/bin/bash -

# @(#) s1       Demonstrate bash pattern matching, variable string.

echo
echo "(Versions displayed with local utility \"version\")"
version >/dev/null 2>&1 && version "=o" $(_eat $0 $1)
set -o nounset

echo
echo " Results:"

file=abcdefgh
echo $file
f1=${file:0:${#file}-2}
echo $f1

echo
my_path=abcdefg-0
echo $my_path
f2=${my_path%[-][0-9]}
echo $f2

echo
my_path=abcdefg-12
echo $my_path
f2=${my_path%[-][0-9][0-9]}
echo $f2

exit 0

Producing:

% ./s1

(Versions displayed with local utility "version")
Linux 2.6.11-x1
GNU bash 2.05b.0

 Results:
abcdefgh
abcdef

abcdefg-0
abcdefg

abcdefg-12
abcdefg

Which may be what secondmouse intended, but Bill's solution is more general ... cheers, drl

[korisk]

file=`ls -t /home/directory | head -n 1 |cut -d"-" -f1-5`
or
file=`ls -t /home/directory | head -n 1 |sed -e 's/-0\$//'`
#??

[packet]

Hello All ,

Thanks for the solutions . I am sorry ,I am not able to tell what exactly i want..... !! In my previous threads .
so the solution given by all is 60 % correct for my problem so I expect you all to come another solution that i am going to explain in detail.

#!/bin/bash

file=`ls -t /home/directory | head -n 1 `

echo $file

# now I have to move the file from /home/directory to /home/anotherdirectory 

mv /home/directory/"$file" /home/anotherdirectory

the /home/directory as three files as below

tr06_2008-11-04_12-09-09_657.34M.jpeg-0
tr06_2008-11-04_12-09-09_657.34M.jpeg-1
tr06_2008-11-04_12-09-09_657.34M.jpeg-2

I want to move two files from the directory to another directory removing the -0 and -2 from the file name .(don't remove other fields ).

two file to move are

tr06_2008-11-04_12-09-09_657.34M.jpeg-0
tr06_2008-11-04_12-09-09_657.34M.jpeg-2

and to another one as remove from the directory or delete from the directory.

one file to delete

tr06_2008-11-04_12-09-09_657.34M.jpeg-1

how ?

I tried with all the solutios that provided like cutting file=`ls -t /home/directory | head -n 1 |cut -d"-" -f1-5`
and
file=`ls -t /home/directory | head -n 1 |sed -e 's/-0\$//'

But when i want move the file it gives an error
saying mv cannot stat $file no file or directory

obviously...!!!

( because when i remove -0 or -2 then in that directory no filename without -0 and -2..!!!! )

Give as early as possible

thanks

[creepy cripple]

mv doesnt move a file from one directory to other; it just changes the file name.

so first change the name, and after that copy the files to destiny directory:

file1="tr06_2008-11-04_12-09-09_657.34M.jpeg-0"
file2="tr06_2008-11-04_12-09-09_657.34M.jpeg-2"

mv $file1 ${file1%-*} #%-* removes the "-0" or "-2"
mv $file2 ${file2%-*}

cp ./$file1 destiny
cp ./$file2 destiny

ciaooooo

[drl]

Hi.

mv doesnt move a file from one directory to other; it just changes the file name.

The command mv means move, and it does move files, provided it is called correctly:

`mv' moves or renames files (or directories).  Synopsis:

     mv [OPTION]... SOURCE DEST
     mv [OPTION]... SOURCE... DIRECTORY

   If the last argument names an existing directory, `mv' moves each
other given file into a file with the same name in that directory.
Otherwise, if only two files are given, it renames the first as the
second.  It is an error if the last argument is not a directory and
more than two files are given.

-- excerpt from info coreutils mv q.v.

There was a notable exception many years ago in early Unix -- directories could not be moved, one needed to tar or cpio them up and then expand them in the appropriate area. That was then and this restriction no longer applies on any modern unix-like system that I have used.

There are situations when a copy (cp) might be appropriate, such as making sure a directory is an exact copy of one from which you are copying, but for most organizing tasks, I use mv ... cheers, drl

[secondmouse]

drl is right. mv is not just for renaming.

packet, try replacing mv /home/directory/"$file" /home/anotherdirectory with
mv /home/directory/"$file"{-0,-2} /home/anotherdirectory

drl's trimming solution seems to work well
file=`ls | head -n 1`
file=${file:0:${#file}-2}
#after that apply your mv command