how to cut string with wildcard (sed)

[slackman]

i got text file and contain....

SKYPE Dec 11 09:26:05 IN=eth0 OUT=eth1 SRC=75.38.161.80 DST=192.168.1.56 PROTO=UDP SPT=30645 DPT=12630 LEN=66
SKYPE Dec 11 09:26:05 IN=eth1 OUT=eth0 SRC=192.168.1.56 DST=118.109.39.86 PROTO=UDP SPT=12630 DPT=15889 LEN=75
SKYPE Dec 11 09:26:05 IN=eth1 OUT=eth0 SRC=192.168.1.56 DST=89.139.194.176 PROTO=UDP SPT=12630 DPT=14056 LEN=75
SKYPE Dec 11 09:26:05 IN=eth1 OUT=eth0 SRC=192.168.1.56 DST=213.250.11.235 PROTO=UDP SPT=12630 DPT=25241 LEN=75
SKYPE Dec 11 09:26:05 IN=eth1 OUT=eth0 SRC=192.168.1.56 DST=212.214.188.162 PROTO=UDP SPT=12630 DPT=54824 LEN=75

i want to cut LEN*,PROTO* and DPT*

i use

cat text.file | sed 's/DPT//'

not working it's cut DPT only

SKYPE Dec 11 09:26:05 IN=eth1 OUT=eth0 SRC=192.168.1.56 DST=212.214.188.162 PROTO=UDP SPT=12630 DPT=54824 LEN=75

result

SKYPE Dec 11 09:26:05 IN=eth1 OUT=eth0 SRC=192.168.1.56 DST=212.214.188.162 PROTO=UDP SPT=12630 =54824 LEN=75


anyone help me.!!!

[fiomba]

You can use cut "delimited" with '='.and then piping
the output through the 2nd cut "delimited" with blank.

cat file| cut -d "=" -f9 | cut -d " " -f1 > len.txt 
cat file| cut -d "=" -f6 | cut -d " " -f1 > proto.txt 
cat file| cut -d "=" -f8 | cut -d " " -f1 > dpt.txt

The results are:

len.txt     --> 66 75 75 75 75
proto.txt   --> UDP UDP UDP UDP UDP
dpt.txt     --> 12630 15889 14056 25241 54824

... obviously, one per line.