Is my output an integer?

[goude]

Hi guys,

I was wondering if someone can help me.
I have written a two line bash script, which is shown below:

df_out=$(command df)
echo $df_out | awk '{print $42}'

The output of this command is 92%, and basically shows the disk usage. (I am trying to write a script which is going to alert me everytime the disk's capacity is over 95%.)

The next step is to write an if statement but before I do, can you please tell whether the output 92% is considered as an integer or not? Is the % sign that worries me. Can I go ahead and write the if statement using the number as it is?

Please ask if I haven't made myself clear.

Thanks a lot.

[vsemaska]

No, 92% isn't an integer because of the percent sign. You have to remove it.

df_out=$(command df) 
nmbr=$(echo $df_out | awk '{print $42}')
nmbr=${nmbr/\%/}
if [ $nmbr -gt 95 ]; then echo "over"; fi

[goude]

Thanks a lot for your answer vsemaska
It works perfectly