Positional variable $#

[Tuxidow]

Hi All,
I am pretty new to the shell scripting. Today I am stuck with the usage of positional variables. I want a shell script which takes input from command prompt, but from the third positional variable onwards what ever i enter should be taken as a single string. for eg: I am entering username password emaild id and then some numbers 234 456 789 ie

#username password emaild id 234 456 789

what ever i entered as numbers should be taken as strings. for this i wrote a script and itz not working fine. Kindly help me to sort this out....

dep="$(4)"

num=$#;

i=5;

while($i -le $num)

do
dep=dep$i;
i=$($i+1);
done


hope my logic is correct. but the output is weird.

[burschik]

There are various ways to do this. First of all, you could require the arguments to be entered properly, e.g.

myscript "234 456 789"

instead of

myscript 234 456 789

If that is not acceptable, you can assign the positional parameters to your variables, then shift the parameters and assign the rest to another variable, i.e.

var1="$1"
var2="$2"
shift 2
rest="$@"

[Tuxidow]

Thank you and itz working fine now...