run the files in order

[rajeshhariharan22]

hi,
i have 10 files which needs to be run one after the other.the run command for each file is something like this

hspice -i <i/p1> -o <o/p1>
hspice -i <i/p2> -o <o/p2>
hspice -i <i/p3> -o <o/p3>
hspice -i <i/p4> -o <o/p4>

i cannot run all at a time
i need to put these commands in a file and they need to be run in order once each file is completed.can anyone help me out how this could be done?

[sdimhoff]

I hope I am understanding your question correctly. If I was doing several things but wanted one line(or file) with the bash code to do it this is how it would go.

1.) I want to run the command "make" then I want to run "make modules_install" ONLY once the first command (make) was done:

$ make && make moduels_install

2.) I want to run a program then immediately run another

$ konqueror & exit

So I think what you want to do is add the double && to the end of each line in your code.

#!/bin/bash
hspice -i <i/p1> -o <o/p1> &&
hspice -i <i/p2> -o <o/p2> &&
hspice -i <i/p3> -o <o/p3> &&
hspice -i <i/p4> -o <o/p4> &&
.... rest of file

Try that and if it isn't what you were looking for let me know.