[SOLVED] Syntax error near unexpected token fi

[Daniel84]

Hello everyone, I am having trouble executing a script

When I try to, I get this:
Line 31: Syntax error near unexpected token fi
Line 31: fi

if test $# = 0
then
	echo
	echo This script requires 1 argument
	exit
fi

declare -i fileCount
declare -i dirCount
declare -i exeCount

	fileCount=0
	dirCount=0
	exeCount=0

for i in $*
do
        if test -f $1
	then
		fileCount=fileCount+1
	fi
	if test -d $1
	then
		dirCount=dirCount+1
	fi
	if test -x $1
	then 
		exeCount=exeCount+1
	fi
done
fi

echo Number of Files found=$fileCount
echo Number of Directories found=$dirCount
echo Number of Executable Files found=$exeCount

[iamagui]

hi Dan,

i am not an expert but guess if you remove the very last 'fi' (after done) guess the script will work.

[Daniel84]

hi Dan,

i am not an expert but guess if you remove the very last 'fi' (after done) guess the script will work.

Ok, I did it and I still got the error message

if test $# = 0
then
	echo
	echo This script requires 1 argument
	exit
fi

declare -i fileCount
declare -i dirCount
declare -i exeCount

	fileCount=0
	dirCount=0
	exeCount=0

for i in $*
do
        if test -f $1
	then
		fileCount=fileCount+1
	fi
	if test -d $1
	then
		dirCount=dirCount+1
	fi
	if test -x $1
	then 
		exeCount=exeCount+1
	fi
done

echo Number of Files found=$fileCount
echo Number of Directories found=$dirCount
echo Number of Executable Files found=$exeCount

[iamagui]

i copied, pasted and ran your script and it ran without any error(s) for me.

[devils casper]

Which distro are you using? Add #!/bin/bash as first line in the script.

#!/bin/bash

if test $# = 0
then
	echo
	echo This script requires 1 argument
	exit
fi

declare -i fileCount
declare -i dirCount
declare -i exeCount
---- ----

[Daniel84]

Thanks for your help. I was editing the backup file instead of the original one which still had the extra 'fi'. It works fine now.