Bash scripting substring

[sroberts82]

Hi,
I need some help writing a regular expression.

I'm doing:

modprobes=(`modprobe -l`)
for filename in "${modprobes[@]}"
do
echo $filename
done

This outputs the likes of:

/lib/modules/2.6.24-23-generic/ubuntu/net/et131x/et131x.ko
/lib/modules/2.6.24-23-generic/ubuntu/net/e1000e-ich9m/e1000e-ich9m.ko
/lib/modules/2.6.24-23-generic/ubuntu/net/atl2/atl2.ko
/lib/modules/2.6.24-23-generic/ubuntu/net/igb/igb.ko
/lib/modules/2.6.24-23-generic/ubuntu/acpi/acer_acpi/wmi-acer.ko
/lib/modules/2.6.24-23-generic/ubuntu/acpi/acer_acpi/acer_acpi.ko
/lib/modules/2.6.24-23-generic/ubuntu/block/drbd/drbd.ko
/lib/modules/2.6.24-23-generic/ubuntu/block/iscsitarget/iscsi_trgt.ko
/lib/modules/2.6.24-23-generic/ubuntu/hwmon/hdaps_ec.ko
/lib/modules/2.6.24-23-generic/ubuntu/misc/pbe5.ko
/lib/modules/2.6.24-23-generic/ubuntu/misc/nozomi.ko
/lib/modules/2.6.24-23-generic/ubuntu/misc/thinkpad_ec.ko
/lib/modules/2.6.24-23-generic/ubuntu/misc/fsc_btns.ko
/lib/modules/2.6.24-23-generic/ubuntu/misc/av5100.ko
/lib/modules/2.6.24-23-generic/ubuntu/misc/ndiswrapper/ndiswrapper.ko

Instead of echoing this, I want to match the name of the module. So, for /lib/modules/2.6.24-23-generic/ubuntu/misc/ndiswrapper/ndiswrapper.ko I want to echo ndiswrapper.

Could someone help? I know its pretty basic but I am new to bash and regexes
Thanks,
Stephen

[WuNMOjTIQanXWBcH]

I'm doing:

modprobes=(`modprobe -l`)
for filename in "${modprobes[@]}"
do
echo $filename
done

This outputs the likes of:

/lib/modules/2.6.24-23-generic/ubuntu/net/et131x/et131x.ko
/lib/modules/2.6.24-23-generic/ubuntu/net/e1000e-ich9m/e1000e-ich9m.ko
/lib/modules/2.6.24-23-generic/ubuntu/net/atl2/atl2.ko
[…]
/lib/modules/2.6.24-23-generic/ubuntu/misc/av5100.ko
/lib/modules/2.6.24-23-generic/ubuntu/misc/ndiswrapper/ndiswrapper.ko

Instead of echoing this, I want to match the name of the module. So, for /lib/modules/2.6.24-23-generic/ubuntu/misc/ndiswrapper/ndiswrapper.ko I want to echo ndiswrapper.

You probably want this:

modprobe -l | sed -e 's/.*\/\(.*\).ko/\1/';

You can apply «sed» in the same way to your version of the code. But I think the principle should be clear.

[alex1983-0112]

or:

modprobes=(`modprobe -l`)
for filename in "${modprobes[@]}"
do
awk '{FS="."; print $1;}' `basename $filename`
done