c question

[jenea]

This is my small script:
============================================
#include <stdio.h>

main ()
{
int num1, counter;

while (num1>0) {
printf ("\nEnter a number:");
scanf ("%d", &num1);
for (counter=0; counter<num1; counter++)
printf ("*");
}
}



What is the simplest way to implement a check on the input. Basically i need to ignore if input is not a number.....

Thank you.

[GNU-Fan]

scanf returns the number of successfully matched tokens (integers in that case). In your case scanf should return either 0 or 1 or EOF.

[gerard4143]

you could try something like....

char ch[2];
int x = 0;
const int MULTI = 10;

ch[1] = '\0';

while ((ch[0] = fgetc(stdin)) != '\n')
{
       if (isdigit(ch[0]))
       {
       x = (x * MULTI) + strtol(ch, NULL, MULTI);
       }
}

of coarse this depends on your definition of number...did you mean digit