BASH - problem with subsequent calls to function with getopts

[dkrysak]

Hi there,

In an attempt to understand getopts better, I wrote a simple function that is a wrapper for rsync. basic stuff.

Now i am trying to make my "-s" a required switch no matter what,

Now when i run a script that calls my below function, the first run goes fine, but then the second instance of my function errors out with the "You have not set the required -s option".

Now if you look in the function, I do have spot that checks for the existence of the -s option..... but from looking at the calling script, you can see that it is there.

Ideas?

Functions.src

function dosync() {
	SRC=
	d=0
	p=0
	s=0
	while getopts "hdp:s:" OPTION
	do
		case $OPTION in

		d)
			DEL=$OPTARG
			d="1"
			;;
		h)
			usage
			exit 1
			;;
		p)
			PORT=$OPTARG
			p="1"
			;;
		s)			
			SRC=$OPTARG
			s=1
			;;
		?)
			usage
			exit 1
			;;
		*)
			usage
			exit 1
			;;
	     esac
	done
	
	if [ $s -ne "1" ]; then
		echo "You have not set the required -s option"
		exit 1
	fi
	
	if [[ "$d" -eq "1" && "$p" -eq "1" ]]; then
		rsync -av --delete -p $PORT -e ssh  $ID@$IP:$SRC $BUFLD
	elif [[ "$d" -eq "1" && "$p" -ne "1" ]]; then
		rsync -av --delete -e ssh  $ID@$IP:$SRC $BUFLD
	elif [[ "$d" -ne "1" && "$p" -eq "1" ]]; then
		rsync -av -p $PORT -e ssh  $ID@$IP:$SRC $BUFLD
	elif [[ "$d" -ne "1" && "$p" -ne "1" ]]; then
		rsync -av -e ssh  $ID@$IP:$SRC $BUFLD
	else
		echo "There seems to be an error with your command"
		exit 1
	fi
}

CALLING (the function) SCRIPT

source functions.src

dosync -s /some/path
dosync -s /some/other/path
dosync -s /some/path2
dosync -s /some/other/path2