sed command to replace directory

[sumathiRaj18]

Hi,

Need to replace dir DIR_SCRIPTS=/user/iprcce/dbg_tool/scripts with DIR_SCRIPTS=$basePath/scripts/scripts.

I tried to replace a directory which is in a variable using sed command. But it didn't work. Can u'll plase help me.

$basePath=/user/iprcce/dbg_tool
sed -e "s/DIR_SCRIPTS=\/user\/iprcce\/dbg_tool\/scripts/DIR_SCRIPTS=\"${basePath}\"\/scripts\/scripts/g
" $TMP > tmp1
mv tmp1 fileout

I am using ksh shell, i have tried some thing like this also sed 's_/i01/proc_/dwftp/scripts_g' ex2 > filename.tmp
but it didnt work.

Thanks in advance!

[Kieren]

From your code it is not clear what you are trying to do. I will assume you are trying to replace all references of "/user/iprcce/dbg_tool/scripts" to "/user/iprcce/dbg_tool/scripts/scripts"

sed -e "s#DIR_SCRIPTS=/user/iprcce/dbg_tool/scripts#DIR_SCRIPTS=/user/iprcce/dbg_tool/scripts/scripts#g $TMP > tmp1

Make sure you set up the variable $TMP to actually be a file before this line

[sumathiRaj18]

About the variable........


need to replace \/user\/iprcce\/dbg_tool with the variable $tmp where $tmp=\/user\/rappikat\/remote2

tried this, but didnt work out. Can u please help me.....

sed -e 's/DIR_SCRIPTS=\/user\/iprcce\/dbg_tool\/scripts/DIR_SCRIPTS="${tmp}"\/scripts\/scripts/g' $TMP
> tmp1

Thanks in advance.

[Kieren]

When setting the variable omit the $

basePath="DIR_SCRIPTS=/user/rappikat/remote2"

Then you can use a sed command:

sed -e "s#DIR_SCRIPTS=/user/iprcce/dbg_tool#$basePath#g" $TMP > tmp1