ssh command with pipe - how to get return code

[Sangal-Arun]

Hello

I'm running a command using ssh:

for ex:

ssh xyz-server "for i in 1 2; do ls -ltr /a/b/c/d; echo; done" | tail


Pls NOTE:
- when im doing "ssh xyz-server" then ssh session is taking me to this server
without giving password.

Question:
If i change the server name to any invalid server name i.e. xyz-server111 or xyz-server222 then i'm getting the below error mesg:

ssh: xyz-server111: Temporary failure in name resolution

and i was trying to get the return code of the ssh command i.e. if the server is not valid (ssh will give this error / will not work/ perform any ls -ltr..) then it will return a non-zero value. But as I'm using "|" at the end of ssh command i'm not able to know whether ssh command actually ran good or not. With "| tail" at the end of ssh command and wrong server name (with above error mesg), i'm getting return code($?)= 0.

Any help!

brgds
/Arun Sangal
720 251 9962

[lomcevak]

Check bash variable PIPESTATUS. It is an array containg the return status of each command in the string of commands that were piped. The ssh command is the 1st command so check element 0.

echo ${PIPESTATUS[0]}

[narayanspg]

use something like this

ssh -T mylinux.com -l username -c "commands to execute with semicolon separated" `<dev/null >/dev/null 2>&1`