bash script filename expansion inside variable

[raphi078]

hi

I want programming a similar system like init-V with the rc2.d/*S scripts like this:

in a folder "$HOME/.modules" are some scripts like this:
10_get_random.sh
12_autoresize.sh
20_add_weather.sh
30_set_wallpaper.sh

ok, how can I start all this scripts in alphabethical order from a other script?

It should test if 10* exist and if yes, execute it, then, inc by one and try 11* to execute it if it exist, and so on... to 99*...

so, I have a flexible system to insert later other modules without changing the main-script (like the Init-V System with the rc?.d)

my example now is this, but the Filename-Expansion don't work right:

     13     i=10
     14     while [[ "$i" -lt 99 ]]; do
     15         EXE_FILE=$HOME/.desk-art/modules/$i*
     16 
     17         # test if filename exist:
     18         if [ -r "$EXE_FILE" ]; then
     19             # exec script:
     20             bash $EXE_FILE
     21         fi  
     22         
     23         # calculate next
     24         i=$[$i+1]
     25     done

any tips for me? (bash-version is 3.2.5)
thank you for your ideas

[meton_magis]

you may want to look into something like this.

cd $HOME/.desk-art/modules/
ls -1 [0-9][0-9]_*.sh | sort -n | awk '{print "./" $1}' | sh

This will execute 1 script at a time (I'm pretty sure anyway) and execute them sequentialy.

it is a lot less code, and is much more efficient since you're not testing 10-99 for if files exist.

[raphi078]

big thanks! Your idea is more usefull than mine. Now, it works fine.

[meton_magis]

cool, glad I could help.

[secondmouse]

You problem can also be solved easily with a single for loop:

for f in $HOME/.desk-art/modules/*.sh; do sh $f; done