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// I want to work with command line arguments //
This is the code thats giving 'Segmentation Fault':
int main(int argc, char * argv[ ] )
{
char * userName;
...
- 10-04-2009 #1Just Joined!
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- Oct 2009
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[SOLVED] Segment Fault
// I want to work with command line arguments //
This is the code thats giving 'Segmentation Fault':
int main(int argc, char * argv[ ] )
{
char * userName;
strcpy(userName, argv[2] );
char * objName;
strcpy(objName, argv[3] )
}
I understand here I attempt to point a read only memory blocks of argv, which was not allowed.
But I don't know how to make my way around. I want to copy the command line arguments (all the strings of argv ) to different variables (here I tried userName and objName pointers).
I don't want to create static arrays for storing them.
I even tried character-by-character copy... given in following code:
char * userName="";
char * objName="";
for(int i=2; i<=3; i++)
{
for(int j=0; j< strlen( argv[ i ] ); j++)
objName[ j ] = argv[ i ][ j ];
}
But even this does not work
Please help !Last edited by namerohit; 10-04-2009 at 07:02 AM. Reason: To format text for better legibility


