bash script in increase by 1, without losing leading zeros

[sirka]

I'm trying to get a command to loop through a number of files that is in the hundreds. The files are named: 001.cvs 002.cvs etc, up to 650.cvs.
I've tried a number of things, mostly around a basic for loop, but cant get bash to not remove the leading zeros.


for i in {001..650}
do
print "$i".cvs
done



There are no files named 1.cvs, only 001.cvs.

I'm considering a really convoluted thing of hard coding the zeros and some kind of checking thing to see how many place there are with a different loop for 1-9, one for 10-99 and 3rd for 100-650 but that seems really stupid and long.

Any one have any suggestions?

thanks

k

[Kieren]

You can just do an ls on the directory if that helps?

for i in `ls *.cvs`
do
print "${i}"
done

[sirka]

unfortunately, no.

My example is a super simplified version of the script, theres some grepping through files and downloading parts based on that (that I have to scp to get and can't ls) and a whole bunch of other things. print was a poor choice because printf would work. but i am trying to using the variable in other commands.

[sirka]

i=`printf '%.03d' $i`

i got it, i think

[nmset]

for i in {0001..1500};do echo $i;done

seems to be what you want.

[sirka]

Your suggestion seems the most logical way to do it to me but I could not get it to work that way. printf re-assignment did work even if it was a kind of backwards way to go about it.